In the dashed case, k is going to be zero or one (a<b is true or false). This wo... | Hacker News

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trelliscoded on July 13, 2017 | parent | context | favorite | on: The long arrow operator in C++

In the dashed case, k is going to be zero or one (a<b is true or false). This works, though:

        int a=0, b=4;

        while(a < - - - - --b) {
                printf("b: %d\n", b);
        }

alejohausner on July 13, 2017 [–]

I just spent an hour constructing a class called Morse such that this outputs "HELLO WORLD!":

    Morse m;
    cout << (++++m) << (+m) << (+-++m) << (+-++m) << (---m) << ", "
         << (+--m) << (---m) << (+-+m) << (+-++m) << (-++m) << "!\n";

Damn you, C++! Why won't you let me overload the . operator? ;-)

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