For any base use the formula: (log base b) a = log(a)/log(b). For eg. google for log(x)/log(2), lg(x), log(x)/log(3)

I believe it's just "lg(x)", though you could also use the more generic case of "log(x)/log(base)"

Try lg(x) ?

that's it, thanks

lg(x) works for me.

thanks!

ln? Isn't log base 2 the natural log?

Yup, that works.

ln should be base e.

Cf. http://en.wikipedia.org/wiki/Natural_logarithm

Oh yes, ok. Ignore my post. I forgot for a second that there was more than 2 numbers in the Universe.