And it uses (or may use) a lock-free implementation on many platforms. | Hacker News

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twsted on Jan 13, 2014 | parent | context | favorite | on: A 30 minute introduction to Rust

And it uses (or may use) a lock-free implementation on many platforms.

dbaupp on Jan 13, 2014 [–]

An atomic increment is still significantly more expensive than a normal one.

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